Question

the sum of three concecutive multiples of 5 is 1110.find these multiple.

Answer 1

Let the first number be x. 

The next number is x+5. 

The next number is x+10.

A.T.Q

x+(x+5)+(x+10)=1110
x+x+5+x+10=1110
3x+15=1110
3x = 1095
x = 365


∴ x = 365

   x + 5 = 365 + 5 = 370

   x + 10 = 365 + 10 = 375

Answer 2

Let the 1st no. Be x
2nd no. Be x+5
3rd no be x+10
So, x+x+5+x+10=1110
3x+15=1110
3x=1110-15
3x=1095
X=1095÷3
X=365
Hence,the first multiple=365
2nd =370 and 3rd=375.