Question

The sum of three conscutive terms is 6, and their product is -91. Given that the diffence is 7. find the first term

Answer 1

Step-by-step explanation:

Let the three consecutive terms be.

a-d, a, a+d

d = 7

a = ?

Sum = 6

a +d +a + a-d = 6

3a = 6

a = 2

so first term is 2

Answer 2

$\Huge{\underline{\underline{\mathfrak{Answer \colon}}}}$

Let a,a + d and a - d be the three consecutive terms

Given

• Sum of the terms = 6 → a + (a + d) + (a - d) = 6.................[1]

• Product of terms = - 91

From equation [1],we get:

$\sf{a + (a + d) + (a - d) = 6} \\ \ \\ \implies \sf{3a + \cancel{d} - \cancel{d} = 6} \\ \\ \implies \: \sf{a = \frac{6}{3} } \\ \\ \implies \: \huge{ \sf{a = 2}}$

Also,

• The common difference of the sequence is 7

Since the terms are of the form (a - d),a and (a + d)

The terms would be:

-5,2,7,....................