the sum of three conseccutive multiples of 3 is 225
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the sum of three consecutive multiples of 3 is 81
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Let the three nos. be 3x, 3(x+1), and 3(x+2)
so BTP,
3x + 3(x+1) + 3(x+2) = 225
or, 9x + 9 = 225
or, 9x = 225 - 9
or, 9x = 216
or, x = 216 ÷ 9
or, x = 24
so, the three nos are 3x = 72
3(x+1) = 75
and 3(x+2) = 78
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