Question

the sum of three consective multiples of 11 is 297.find the numbers

Answer 1

Step-by-step explanation:

$\frak Given = \begin{cases} &\sf{The\ sum\ of\ three\ consecutive} \\ &\sf{multiples\ of\ 11\ is\ 297.} \end{cases}$

To find:- We have to find the numbers?

☯️ Let the three multiples be 11x, 11x + 11, and 11x + 22.

__________________

$\frak{\underline{\underline{\dag According\ to\ the\ question:-}}}$

$\sf : \implies {11x\ +\ 11x\ +\ 11\ +\ 11x\ +\ 22\ =\ 297} \\ \\ \sf : \implies {33x\ +\ 33\ =\ 297} \\ \\ \sf : \implies {33x\ =\ 297\ -\ 33} \\ \\ \sf : \implies {x\ =\ \dfrac{294}{33}} \\ \\ \sf : \implies {\purple{\underline{\boxed{\bf x\ =\ 8.90\ =\ 9.}}}}\bigstar$

● So the value of x is 9.

___________________

$\frak{\underline{\underline{\dag So\ here:-}}}$

$\sf : \implies {11x\ =\ 11\ ×\ 9\ =\ 99.}$

$\sf : \implies {11x\ +\ 11\ =\ 11\ ×\ 9\ +\ 11\ =\ 110.}$

$\sf : \implies {11x\ +\ 22\ =\ 11\ ×\ 9\ +\ 22\ =\ 121.}$

Hence:-

$\sf \therefore {\underline{The\ required\ numbers\ are\ 99,\ 110,\ and\ 121.}}$

Answer 2

Answer:

$Step-by-step explanation:</p><p></p><p>[tex]\frak Given = \begin{cases} &\sf{The\ sum\ of\ three\ consecutive} \\ &\sf{multiples\ of\ 11\ is\ 297.} \end{cases}$

To find:- We have to find the numbers?

☯️ Let the three multiples be 11x, 11x + 11, and 11x + 22.

__________________

$\frak{\underline{\underline{\dag According\ to\ the\ question:-}}}$

$\sf : \implies {11x\ +\ 11x\ +\ 11\ +\ 11x\ +\ 22\ =\ 297} \\ \\ \sf : \implies {33x\ +\ 33\ =\ 297} \\ \\ \sf : \implies {33x\ =\ 297\ -\ 33} \\ \\ \sf : \implies {x\ =\ \dfrac{294}{33}} \\ \\ \sf : \implies {\purple{\underline{\boxed{\bf x\ =\ 8.90\ =\ 9.}}}}\bigstar$

● So the value of x is 9.

___________________

$\frak{\underline{\underline{\dag So\ here:-}}}$

$\sf : \implies {11x\ =\ 11\ ×\ 9\ =\ 99.}$

$\sf : \implies {11x\ +\ 11\ =\ 11\ ×\ 9\ +\ 11\ =\ 110.}$

$\sf : \implies {11x\ +\ 22\ =\ 11\ ×\ 9\ +\ 22\ =\ 121.}$

Hence:-

$\sf \therefore {\underline{The\ required\ numbers\ are\ 99,\ 110,\ and\ 121.}}$[/tex]