Question

the sum of three consective
multiples of 8 is 88. find the
multiple​

Answer 1

Answer:The third consecutive multiple of 8 be 8(x+2). It is given that the sum of all the three consecutive multiples of 8 is 888. Therefore the first multiple of 8 is 8x, by substituting the value of x in the equation we get, ⇒8×36=288.

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Answer 2

Answer:

288; 296; 304

Step-by-step explanation:

Let 3 consecutive multiple of 8

8x,8(x+1),8(x+2)

Sum=8x+8(x+1)+8(x+2)=888

8(x+x+x+1+2)=888

3(x+1)=111

x+1= 111/3

x+1=37

x=36

First multiple =8x=8×36= 288

Second =8(x+1)=8×37= 296

Third =8(x+2)=8×38= 304

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