The sum of three consective multiplies of 11 is 363. Find the multiples.
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First let's divide 363 by 11
= 363 / 11
= 33.
According to the question :
Now let the number be ' x '
Then, consecutive integers will be :
x + ( x + 1 ) + ( x + 2 ) = 33
3x + 3 = 33
3x = 33 - 3
3x = 30
x = 30 / 3
x = 10.
First number = x × 10 = 11 × 10 = 110.
Second number = x × 11 = 11 × 11 = 121.
Third number = x × 12 = 11 × 12 = 132.
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