The sum of three consecutive add no is 62 find the number
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Answer:
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Step-by-step explanation:
let. take x , x+ 1, x+2
x + x+ 1+ x+ 2= 62
3x + 3 = 62
3x= 62-3
3x=59
x= 59/3
x= 19.6
- x+1=19.6+1=20.6
- x+2=19.6+2=21.6
Answered by
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we know that the sum of three consecutive odd number is =62
let first number is=x
another number is=x+2
last nut is=x+2+2
now according to the question the sum of three consecutive number is=62
x+(x+2) +(x+2+2)
x+x+x+2+2+2
3x+6
3x=62_6
3x=56
x=56÷3
x+2=56÷3+2
=62÷3
x+2+2=62÷3+2
=68÷3
so the three consecutive odd number are( 1st number) =56÷3
(2nd number is)
=62÷3
(3rd number is 68÷3
these numbers are in fractional form , because if we will find the value for each equation then the value that we get also in fractional form
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