Question

the sum of three consecutive arithematic sequence is 30 and their product is 910.find the terms





plz tell the way also​

Answer 1

Answer:

Answer is given below

Step-by-step explanation:

Let the terms be (a-d) (a) and (a+d)

Sum =30

a-d+a+a+d=30

3a=30

a=10

Given product =910

(a-d)a(a+d)=910

(a^2-d^2)a=910

But, a=10

(10a^2 - d^2)*10=910

100-d^2=91

100-91=d^2

d^2=9

d= +3

So,the numbers are a-d=10+3=13

a=10

a+d=10+(3)

=10-3

=7

a-d=10-(+3)

=10-3

=7

a=10

a+d=10+3

=13

If it is correct plz mark me as brainliest and thank you