The sum of three consecutive even integer is 54 what is smallest no
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Answered by
2
Answer:
Step-by-step explanation:
Let the three consecutive even integer number = x, x+1, x+2
Since , their sum = 54
So , x+ x+1 + x+2 = 54
3x+3 =54
3x=54-3
3x=51
x=51÷3
x=27
The smallest number = 27
Answered by
2
Step-by-step explanation:
let three consecutive even integer is
x,x+2,x+4
ATQ
x+x+2+x+4=54
3x+6=54
3x=54-6
3x=48
x=48/3
x=16
so,
x+2=18
x+4=20
The smallest number is 16
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