Question

The sum of three consecutive even integers is 48. Find the middle integer .
pls answer fast with step by step . tomorrow is my exam ​

Answer 1

Answer:

16

Step-by-step explanation:

let the integer be x

Then the three consecutive integers are x, x+1 and x +2

ATQ, x+x+1+x+2=48

        3x+3=48

        3x=45

        x=15

middle integer will be x+1 = 15+1= 16

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Answer 2

Answer:

suppose the first number of all three consecutive number is "a".

(a+2) and (a+4) will be the next two numbers .

a+a+2+a+4=48

3a+6=48

3a=48-6

3a=42

a=42/3

a=14

there fore a=14, a+2=16, a+4=18

Hence the three consecutive numbers are 14,16 and 18