the sum of three consecutive even integers is 66 find all the three integers
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Let one no. be x
Another no. be x+1
and next no. be x+2
Sum of the no. are 66
So,x+x+1+x+2=66
3x+3=66
3x=66-3
3x=63
x=63/3
x=21
x+1=21+1=22
x+2=21+2=23
Another no. be x+1
and next no. be x+2
Sum of the no. are 66
So,x+x+1+x+2=66
3x+3=66
3x=66-3
3x=63
x=63/3
x=21
x+1=21+1=22
x+2=21+2=23
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