Math, asked by sha48, 1 year ago

the sum of three consecutive even know even natural number is 48 find the greatest of these number

Answers

Answered by Anonymous
0
Hey dear!!


Here is yr answer....


Given,

Sum of the three consecutive even no. = 48

Now,

let the nos. be x, x+2 , x+4


x+x+2+x+4 = 48

3x+6 = 48

3x = 48-6

3x = 42

x = 42/3

x = 14


1st no. => 14



= x+2

= 14+2

= 16


2nd no. => 16



= x+4

= 14+4

= 18


3rd no. => 18


The nos. are 14 , 16 , 18


The greastest is 18


Hope it hlpz...
Answered by anisha28
2
hey dear here's ur answer
let one of the consecutive integers be x
so the second integer is x+2
and the third one is x+4
so the equation will be formed like this...
x+x+2 +x+4 =48
which implies 3x=42
or x=14
so we got the numbers finally
so the first number is 14
and second number is x+2= 2+14=16
and the third one is x+4 = 14+4=18
and 14 + 16+ 18 is 48.. and all the numbers are even too..
and greatest of these is 18..
hope it helps.
with loving regards
@anisha28☺☺☺
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