Question

the sum of three consecutive even natural number is 48. find the greatest of these numbers​

Answer 1

Let first even number be n

Second even no. Be n+2

Let third even no. Be n+4

Their total is 48

Therefore

n + (n+2)+(n+4)=48

3n+6=48

3n=48-6

3n=42

n=42/3

n=14

Second no = n+2= 14+2=16

Third no=n+4=14+4=18

No.1 =14

No.2=16

No.3=18

Answer 2

hyy dear

Here is your answer

Let ,

The first even number be x

The second even number be x+2

The three even number be x+3

Sum three consecutive even number is 48

ATQ

x + ( X + 2 ) + [ ( X + 2 ) + 2 = 48

X + X + X + 2 + 2 + 2 = 48

3x + 6 = 48

3x = 48 - 6

3x = 42

X = 42 / 2

X = 14

The 3 consecutive number would be :

The first even number => X = 14

The second even numbers => ( X + 2 ) = 14 + 2 = 16

The third even number => ( X + 2 ) + 2 = 14 + 4 = 18

The largest amongst them is 16

Hope it's helps you

Plz marked in brainlest answer