The sum of three consecutive even natural numbers is 48. Find the greatest of these numbers
Answers
Answer:
18
Solution:
Let's the three consecutive even natural numbers as follow ↓
1st even no. = x
2nd even no. = x + 2
3rd even no. = x + 4
Now,
According to the question ,
The sum of the required even natural numbers is 48 .
Thus,
=> x + x + 2 + x + 4 = 48
=> 3x + 6 = 48
=> 3x = 48 - 6
=> 3x = 42
=> x = 42/3
=> x = 14
Thus ,
1st even no. = x = 14
2nd even no. = x + 2 = 14 + 2 = 16
3rd even no. = x + 4 = 14 + 4 = 18
Clearly ,
18 is the greatest among all these three even numbers .
Hence,
Required answer is 18 .
Answer:
18
Step-by-step explanation:
Solution:
Let's the three consecutive even natural numbers as follow ↓
1st even no. = x
2nd even no. = x + 2
3rd even no. = x + 4
Now,
According to the question ,
The sum of the required even natural numbers is 48 .
Thus,
==> x + x + 2 + x + 4 = 48
=> 3x + 6 = 48
=> 3x = 48 - 6
=> 3x = 42
=> x = 42/3
=> x = 14
Thus ,
1st even no. = x = 14
2nd even no. = x + 2 = 14 + 2 = 16
3rd even no. = x + 4 = 14 + 4 = 18
Clearly ,
18 is the greatest among all these three even numbers .
Hence,
Required answer is 18 .