the sum of three consecutive even natural numbers is 48.find the greatest of these?
Answers
Answered by
9
Heya!!Here is your answer friend ⤵⤵
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Let the first number be X
The other number becomes , X+2 and X+4
We are given ,
X+X+2+X+4=48
3X+6=48
3X=42
X=14
Therefore the numbers are 14,16 and 18
Hence the largest of these is 18
Hope it helps you ✌✌
---------------------
-----------------------------
Let the first number be X
The other number becomes , X+2 and X+4
We are given ,
X+X+2+X+4=48
3X+6=48
3X=42
X=14
Therefore the numbers are 14,16 and 18
Hence the largest of these is 18
Hope it helps you ✌✌
sanya55:
there is no need
Answered by
3
Let the three consecutive even natural numbers be x, x+2,x+4.
A/q
x+x+2+x+4 = 48
3x+6 = 48
3x = 48-6
3x = 42
x = 42/3
x = 14
e5
A/q
x+x+2+x+4 = 48
3x+6 = 48
3x = 48-6
3x = 42
x = 42/3
x = 14
e5
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