the sum of three consecutive even natural numbers is 78 find the greatest of these numbers
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In any event, this sum must be even, so 3 consecutive even integers would be n, n+2 & n+4 whose sum is 3n + 6.
Set that to either 78 or 7878, whichever is intended, & solve for n. If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.
Set that to either 78 or 7878, whichever is intended, & solve for n. If 78 is their grand total, then those 3 consecutive even numbers have to be 24, 26 & 28.
GunjanJathliya:
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Here's your answer..
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Let ,
The first even number be x
The second even number be(x+2)
The third even number be (x+2)+2
Sum of three consecutive even numbers is 78
A/q
x + (x+2) + [(x+2)+2 = 78
x+x+x+2+2+2=78
3x + 6 = 78
3x = 78–6
3X= 72
X=24
The 3 consecutive number would be:-
The first even number => x = 24
The second even number =>(x+2) =24+2=26
The third even number => (x+2)+2=24+4=28
The largest amongst them is 28
Hope it helps you
____________________
Let ,
The first even number be x
The second even number be(x+2)
The third even number be (x+2)+2
Sum of three consecutive even numbers is 78
A/q
x + (x+2) + [(x+2)+2 = 78
x+x+x+2+2+2=78
3x + 6 = 78
3x = 78–6
3X= 72
X=24
The 3 consecutive number would be:-
The first even number => x = 24
The second even number =>(x+2) =24+2=26
The third even number => (x+2)+2=24+4=28
The largest amongst them is 28
Hope it helps you
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