the sum of three consecutive even no. is 210. find the largest of these no.
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Answered by
1
Answer:
1st no. : 2n
2nd no.: 2n+2
3rd no.: 2n+4
2n+2n+2+2n+4=210
6n+6=210
6(n+1)=210
n+1=35
n=34
therefore largest no. is 2n+4 = 2*34+4=72
Answered by
2
Let,three consecutive even numbers=2n,2n+2,2n+4
=2n+2n+2+2n+4=210
=6n+6=210
=6n=210-6
n=204/6
n=36
Therefore,2n=2(36)
=72
2n+2=2(36)+2
=72+2=74
2n+4=2(36)+4
=72+4=76
Hence three consecutive numbers are 72,74 and 76
=2n+2n+2+2n+4=210
=6n+6=210
=6n=210-6
n=204/6
n=36
Therefore,2n=2(36)
=72
2n+2=2(36)+2
=72+2=74
2n+4=2(36)+4
=72+4=76
Hence three consecutive numbers are 72,74 and 76
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