Question

The Sum of three consecutive even number is 426.find the largest number of the three consecutive numbers.

Answer 1

Answer:

Step-by-step explanation:

Here we will use algebra to find three consecutive integers whose sum is 426. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 426. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 426

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 426

3X + 3 = 426

3X + 3 - 3 = 426 - 3

3X = 423

3X/3 = 423/3

X = 141

Which means that the first number is 141, the second number is 141 + 1 and the third number is 141 + 2. Therefore, three consecutive integers that add up to 426 are 141, 142, and 143.

141 + 142 + 143 = 426

We know our answer is correct because 141 + 142 + 143 equals 426 as displayed above.

Answer 2

Answer

x = first integer

x + 2 = second integer (since it's even, it increases by 2)

x + 4 = third integer (same thing)

x + x + 2 + x + 4 = 426

3x + 6 = 426

3x = 420

x = 140

x + 2 = 142

x + 4 = 144

140 + 142 + 144 = 426

So your numbers are 140, 142, and 144.

Step-by-step explanation:

Hope it helps.....