The sum of three consecutive even
number is 48 find the smallest
number
Answers
Answered by
5
Answer:
next two numbers will be a + 2, a + 4. It is given that sum of all these three consecutive numbers is 48. Hence the three consecutive numbers are 14, 16, 18. The smallest of all these numbers are 14.
Explanation:
Answered by
0
Answer:
Let us assume the three consecutive even number of series to be x,x+2 and x+4
So the sum of consecutive even number=48=x+x+2+x+4
=>48=3x+6
=>-3x=6-48
=>-3x=-42
=>x=14
Therefore three consecutive even number are
x=14
x+2=14+2=16
x+4=14+4=18
So, smallest of this number is 14.
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