Question

the sum of three consecutive even number is 63 . find the number​

Answer 1

Step-by-step explanation:

x+x+1+x+2=63

3x+3=63

3x=63-3

3x=60

x=20

x=20,x+1=21,x+2=22

Answer 2

Answer:

Step-by-step explanation:

Here is your solution

Let,

The first odd integer be:x

Then the second odd integer is:-

x+2

Then the third odd integer is:-

x+2+2=x+4

Sum of three consecutive odd numbers =63

A/q

(x)+(x+2)+(x+4)=63

3x+6=63

3x=63-6

3x=57

x=19

now

The first integer is: x = 19

the second integer is: x+2 = 19+2 = 21

the third integer is: x+4 = 19+4 = 23

____________ii method ________

Let the three odd numbers be x,[x+2], and [x+4] which gives 63 when they are summed.

i.e; x+x+2+x+4=63;

3x+6=63; 

3x=63-6;

3x=57;

x=57/3;

x=19.

therefore, x+2 = 19+2; x+2= 21.

x+4 = 19+4; x+4 = 23.

Hence 19, 21 and 23 are the three consecutive odd numbers which give 63 when adding these numbers.

____________________________

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