Question

The. Sum of three consecutive even number is72. Find the numbers

Answer 1

$<b><u><i> Heya mate!!! Here's your solution</i></u>$
______________________________

$\huge{Given,}$

The sum of three consecutive even numbers even number is 72.

$\huge{To\: Find}$

Find the numbers.

$\huge{Solution}$

Firstly,

$\mathcal{\blue{Even \:numbers}}$ are numbers which are divisible by 2. Example - 2, 4, 50...1000, and so on.

And,
$\mathcal{\blue{Consecutive\: numbers}}$ are numbers which come just after any number. Example - 1-2-3, 7-8-9, 98-99-100 and so on.

Hence,$\mathcal{\blue{even\: consecutive \:numbers}}$ will be numbers with an interval of two numbers. Example, 2-4-6, 96-98-100; and so on.
______________________________

Now,

Let the first number be x.

Then, second number = x + 2

And, third number = x + 4

Also, their sum is 72.
__________________

Hence, according to question,

x + (x + 2) + (x + 4) = 72

=> x + x + x + 2 + 4 = 72

=> 3x + 6 = 72

=> 3x = 72 - 6

=> 3x = 66

=> x = 66/3

=> x = 22

Hence, the numbers are

x = 22
x + 2 = 22 +2 = 24
x + 4 = 22 + 4 = 26
__________________

Finally,

Your answer is

$\boxed{\bold{\pink{\mathcal{22;\:24;\:and\: 26}}}}$
______________________________

$\huge{\bold{\red{\mathfrak{Thank\: you}}}}$

Answer 2

Here is your solution

Given:-

sum of three consecutive even numbers is 72

Let
Number be x,x+2,x+4

Now

A/q

x+(x+2)+(x+4)=72
3x+6=72
3x=72-6
3x=66
x =22

Hence Number are:-
x=22
x+2=22+2=24
x+4=22+4=26

The three consecutive even numbers are 22,24,26

Hope it helps you