Question

The sum of three consecutive even numbers is 126. What is the difference between twice the lowest one and one-half of the highest one?​

Answer 1

Answer:

x+x+2+x+4=126

3x+6=126

3x=126-6=120

x=120÷3=40

numbers= x=40

x+2=42

x+4=44

40×2-44×1/2

80-22

=58

Answer 2

Step-by-step explanation:

Answer:

x+x+2+x+4=126

3x+6=126

3x=126-6=120

x=120÷3=40

numbers= x=40

x+2=42

x+4=44

40×2-44×1/2

80-22

=58