Question

The sum of three consecutive even numbers is 252. Find
them

Answer 1

Answer:-

Let the numbers be 2x,2x+2,2x+4

Therefore,

According to the given condition,

$\sf \small 2x + 2x + 2 + 2x + 4 = 252$

$\sf \implies\small 6x + 6= 252$

$\sf \implies\small 6(x + 1)= 252$

$\sf \implies\small (x + 1)= 42$

$\sf \implies\small x= 41$

So,

$\sf \small 2x = 2 \times 41 = 82$

$\sf \small 2x + 2 = 2 \times 41 + 2 = 84$

$\sf \small 2x + 4 = 2 \times 41 +4= 86$

Hence, the numbers are, 82,84 and 86.

Answer 2

Answer:

Let the numbers be 2x,2x+2,2x+4

Therefore,

According to the given condition,

\sf \small 2x + 2x + 2 + 2x + 4 = 2522x+2x+2+2x+4=252

\sf \implies\small 6x + 6= 252⟹6x+6=252

\sf \implies\small 6(x + 1)= 252⟹6(x+1)=252

\sf \implies\small (x + 1)= 42⟹(x+1)=42

\sf \implies\small x= 41⟹x=41

So,

\sf \small 2x = 2 \times 41 = 822x=2×41=82

\sf \small 2x + 2 = 2 \times 41 + 2 = 842x+2=2×41+2=84

\sf \small 2x + 4 = 2 \times 41 +4= 862x+4=2×41+4=86

Hence, the numbers are, 82,84 and 86.