The sum of three consecutive even numbers is 42. Find the numbers.
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let the numbers be x,x+2,x+4
given= 3x+6=42 x=12
hence the numbers are
12,14,16
Answered by
3
Step-by-step explanation:
We can call the lowest integer x, the next integer x+2 (since our integers need to be even) and the third integer x+4. Now we can set up an algebraic equation. 42=x+(x+2)+(x+4).
Combine like terms on the right side,
42= 3x+6.
Subtract 6 from each side
36=3x
Divide each side by 3
x=12, which is our lowest integer.
The next two integers we find with 12+2=14 and 12+4=16. Or just simply take the next two even integers. Thus, 12+14+16=42.
Hope this helps.
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