the sum of three consecutive integer is 5 more than the smallest of the integers
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rkjnv723:
wrong.. because...sum of these inters is 6
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Let the smallest integer be x
Then according to question,
=> x + x + 1 + x + 2 = x + 5
=> 3x + 3 = x + 5
=> 3x - x = 5 - 3
=> 2x = 2
=> x = 1
The integers are-
x = 1
x + 1= 1+1 =2
x +2= 1+2=3
Thanks
Let the smallest integer be x
Then according to question,
=> x + x + 1 + x + 2 = x + 5
=> 3x + 3 = x + 5
=> 3x - x = 5 - 3
=> 2x = 2
=> x = 1
The integers are-
x = 1
x + 1= 1+1 =2
x +2= 1+2=3
Thanks
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