The sum of three consecutive integer is 63. find the integer?
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Answered by
9
Define x:
Let one number be x
The other 2 numbers are (x + 1) and (x + 2)
Solve x:
The sum is 63
x + (x + 1) + (x + 2) = 63
x + x + 1 + x + 2 = 63
3x + 3 = 63
3x = 60
x = 20
Find the numbers:
First number = x = 20
Second number = x + 1 = 20 + 1 = 21
Third number = x + 2 = 20 + 2 = 22
Answer: The 3 numbers are 20, 21 and 22
Answered by
2
~*HEY FRIEND*~
~* THE ANSWER OF YOUR QUESTION IS..*~
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let the consecutive integers be
x + (x+1) +(x +2) = 63
3x + 3 =63
3x =60
x=20
hence , the integers are
20 , 21, 22
HOPE IT WILL HELP YOU
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________
let the consecutive integers be
x + (x+1) +(x +2) = 63
3x + 3 =63
3x =60
x=20
hence , the integers are
20 , 21, 22
HOPE IT WILL HELP YOU
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