Question

the sum of three consecutive integer is48 find three integer​

Answer 1

Answer:

Let first number be x

second number be x-1

third number be x+1

a/q

    x+x-1+x+1 = 48

    x+x+x+1-1 = 48

    3x = 48

     x = 48/3

     x = 16

Therefore,

first number = x = 16

second number = x-1 = 16-1 = 15

third number = x+1 = 16+1 = 17

Answer 2

Answer:

let the first integer be X

then, the second integer=X +1

the third integer=X+2

a/q

X+X+1+X+2=48

=3x+3=48

=3x=48-3

=3x=45

X=45/3

=15

so the first integer is X =15

the second integer is X+1=16

the third integer is X+2=17