Question

the sum of three consecutive integers are such that takemin increasing order and multiplies by 2,3,4 respectively and add upto74 find these numbers

Answer 1

Let the required three consecutive integers are x , ( x + 1 ) and ( x + 2 )

According to the question,

when taking in increasing order and 1st number is multiplied by 2nd number is multiplied by 3 and 3rd number is multiplied by 4 there sum becomes 74 .

So,

2( x ) + 3( x + 1 ) + 4( x + 2 ) = 74

Opening brackets,

2x + 3x + 3 + 4x + 8 = 74

2x + 3x + 4x + 3 + 8 = 74

9x + 11 = 74

9x = 74 - 11

9x = 63

$x =\frac{63}{9}\\ \\ \\ \boxed{ \bold{ x = 7 }}$

Hence, Numbers are

x = 7

x + 1 =7 + 1 = 8

x + 2 = 7 + 2 = 9

Answer 2

уσυя αиѕωєя !!

lєt thє thrєє cσnѕєcutívє numвєrѕ:

х, х + 1, х + 2

ᴛᴀᴋɪɴɢ ɪɴ ɪɴᴄʀᴇᴀsɪɴɢ ᴏʀᴅᴇʀ!

ᴍᴜʟᴛɪᴘʟʏ ᴛʜᴇ ɴᴜᴍʙᴇʀs ᴡɪᴛʜ 2, 3, 4

ᴛʜᴇɪʀ sᴜᴍ = 74

ᴀᴛǫ ʏᴏᴜʀ ᴇǫᴜᴀᴛɪᴏɴ ʙᴇᴄᴏᴍᴇs:

$= > 2(x) + 3(x + 1) + 4(x + 2) = 74 \\ \\ = > 2x + 3x + 3 + 4x + 8 = 74 \\ \\ = > 9x + 11 = 74 \\ \\ = > 9x = 74 - 11 \\ \\ = > 9x = 63 \\ \\ = > x = \frac{63}{9} \\ \\ = > x = 7$

ғɪʀsᴛ ᴄᴏɴsᴇᴄᴜᴛɪᴠᴇ ɴᴏ. = x = 7

sᴇᴄᴏɴᴅ ᴄᴏɴsᴇᴄᴜᴛɪᴠᴇ ɴᴏ. = x + 1 = 7 + 1 = 8

ᴛʜɪʀᴅ ᴄᴏɴsᴇᴄᴜᴛɪᴠᴇ ɴᴏ. = x + 2 = 7 + 2 = 9

тнαикѕ !!