Math, asked by us9108155, 2 months ago

The sum of three consecutive integers is 10 more than twice the smallest of the integers.Find the integers.​

Answers

Answered by nirupamaprutwiraj
1

Step-by-step explanation:

let the integers be x, x+1,x+2

x+x+1+x+2=2x+10

3x+3=2x+10

3x-2x=10-3

x=7

Answered by Clαrissα
5

Answer:

 \large{ \boxed{ \underline{ \rm{7,8,9}}}}

  • The integers are 7,8 and 9

Step-by-step explanation:

Given :

  • Sum of three consecutive integers is 10 more than twice the smallest of the integers.

To Find :

  • The integers.

Solution :

Let's assume the integers as :-

  • x
  • x + 1
  • x + 2

So, firstly let's calculate the value of x,

 \implies \rm \: x +( x + 1) + (x  + 2) = 10 + 2x \\  \\  \\  \implies \rm 3x + 3 =10 + 2x \\  \\  \\  \implies { \boxed{\bf \: x = 7}}

Hence, value of x is 7.

Now, let's calculate the remaining numbers :

 \tiny \dag \: { \underline{ \bf{First \: case}}}

 \implies \rm \: x + 1 \\  \\  \\  \implies \rm \: 7 + 1 \\  \\  \\  \implies \bf \: 8

Therefore, the second number is 8.

 \tiny \dag \: { \underline{ \bf{Second \: case}}}

\implies \rm \: x + 2 \\  \\  \\  \implies \rm \: 7 + 2 \\  \\  \\  \implies \bf \: 9

Therefore, the third number is 9.

Henceforth,

  • The integers are 7,8 & 9
Similar questions