Question

The sum of three consecutive integers is 102. find the lowest of the three

Answer 1

Let integers be x-1, x and x+1.
According to Question,
x-1+x+x+1 = 102
3x = 102
x = 34
Hence, required smallest no. is 33.

Answer 2

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☸ Required Answer is ⬇⬇⬇⬇

Given, Sum = 102

⭕ Let the three consecutive Integers are x-1 , x , x+1.


A.T.Q

x-1+x+x+1 = 102

3x=102

x= 102/3

x = 34


Therefore the three integers are :

1. x-1 = 34-1 = 33

2. x =34

3. x+1 = 34+1 = 35


Least integer among them is 33.


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