The sum of three consecutive integers is 102. find the lowest of the three
Answers
Answered by
9
Let integers be x-1, x and x+1.
According to Question,
x-1+x+x+1 = 102
3x = 102
x = 34
Hence, required smallest no. is 33.
According to Question,
x-1+x+x+1 = 102
3x = 102
x = 34
Hence, required smallest no. is 33.
Answered by
6
Holla ^_^
☸ Required Answer is ⬇⬇⬇⬇
Given, Sum = 102
⭕ Let the three consecutive Integers are x-1 , x , x+1.
A.T.Q
x-1+x+x+1 = 102
3x=102
x= 102/3
x = 34
Therefore the three integers are :
1. x-1 = 34-1 = 33
2. x =34
3. x+1 = 34+1 = 35
Least integer among them is 33.
Vielen Dank ♥
☸ Required Answer is ⬇⬇⬇⬇
Given, Sum = 102
⭕ Let the three consecutive Integers are x-1 , x , x+1.
A.T.Q
x-1+x+x+1 = 102
3x=102
x= 102/3
x = 34
Therefore the three integers are :
1. x-1 = 34-1 = 33
2. x =34
3. x+1 = 34+1 = 35
Least integer among them is 33.
Vielen Dank ♥
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