Question

The sum of three consecutive integers is 12 more than twice the smallest of the integers. Find all integers​

Answer 1

Answer:

let the nos. be x-1,x,x+1

Step-by-step explanation:

x-1+x+x+1=2(x-1)+12

3x=2x+2+12

3x-2x=14

x=14

therefore nos are 13,14,15

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Answer 2

Answer:

let the integers be x,x+1,x+2

x+x+1+x+2=12+2x

3x+3=12+2x

3x-2x=12-3

x=9    x+1=10,x+2=11

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Step-by-step explanation: