Question

The sum of three consecutive integers is − 126. What are the integers?

Answer 1

let the 1st integer be x
2nd x+1
3rd x+2
A/q x +x+1+x+2 = -126
3x+3=-126
3(x+1)=-126
x+1=-126/3
x+1=-42
x= -42 -1
x= -43

Answer 2

let the three consecutive integers x, x+1,x+2
sum=-126
x+x+1+x+2=-126
3x+3=-126
3x=-126-3
3x=-129
x=-129/3
x=-43
therefore required integers are -43, -42, -41