Question

The sum of three consecutive integers is 15 more then the smallest of the integers . find the integers​

Answer 1

Answer:

x,x+1,x+2=15

u can solve ......

the questions

Answer 2

Given,

The sum of 3 consecutive integers is 15 more than the smallest of these.

To find,

The integers.

Solution,

First of all, let the three consecutive integers be

x,

x + 1, and,

x + 2.

We can simply add them all to find the sum. So,

sum = x + (x + 1) + (x + 2)

sum = 3x + 3

It is given that the sum is 15 more than the smallest integer.

From the assumed integers x will be the smallest. So, this can be expressed mathematically as,

(3x + 3) = (x + 15)

Simplifying the above expression,

3x - x = 15 - 3

⇒ 2x = 12

⇒ x = 6.

So, first integer = x = 6.

From this value of x, we can find other integers as follows.

2nd integer = x + 1 = 6 + 1 = 7, and,

3rd integer = x + 2 = 6 + 2 = 8.

Therefore, the three consecutive integers will be 6, 7, and, 8.