Question

The sum of three consecutive integers is 237. Find the integers.
(Enter only the integer in the boxes and in the ascending order)​

Answer 1

Answer:

78,79,80

Step-by-step explanation:

let the smallest integer in the series be x

x + x + 1 + x + 2 = 237

3x + 3 =237

3x = 237-3 = 234

x = 234/3 = 78

x + 1 = 79

x + 2 = 80

Answer 2

Answer:

The three consecutive numbers are 78,79&80 Verify:-(78+79+80=237)