Question

The sum of three consecutive integers is 24. Find the smallest integer.​

Answer 1

Step-by-step explanation:

Let us set the first of the three integers as n. Therefore, the number after would be n+1 and the next would be n+2.

24 = n+(n+1)+ (n+2)

24 = 3n+3

n = 7

Thus, the three consecutive numbers would be 7,8,9.

Answer 2

Answer:

Let one integer be x.

Other be x+1

Another be x+2

So three consecutive numbers be ,x ,x+1 , x+2

So x+1+x+x+2=24

$3x + 3 = 24 \\ 3x = 24 - 3 = 21 \\ 3x = 21 \\ x = 21 \div 3 \\ = 7$

So one number is 7

Other number is 7+1=8

another number is 7+2=9

Smallest among them is 7

Hope it helps

Aastha