Question

the sum of three consecutive integers is 30 e then stri least number is​

Answer 1

Given :-

• The sum of three consecutive integers is 30.

To find :-

• Leat number

Solution :-

Let the conservative numbers be x, (x + 1), (x + 2)

• Sum of three consecutive numbers = 30

According to the given condition

→ x + (x + 1) + (x + 2) = 30

→ x + x + 1 + x + 2 = 30

→ 3x + 3 = 30

→ 3(x + 1) = 30

→ x + 1 = 30/3

→ x + 1 = 10

→ x = 10 - 1

→ x = 9

Hence,

• x = 9

Therefore,

• First number = x = 9
• Second number = x + 1 = 10
• Third number = x + 2 = 11

→ So least number is 9

Answer 2

Answer:

✳️ Given ✳️

$\leadsto$ The sum of three consecutive integers is 30.

✳️ To Find ✳️

$\leadsto$ What is the least number.

✳️ Solution ✳️

✒️ Let,

• First consecutive number be x
• Second consecutive number be (x + 1)
• Third consecutive number will be be (x + 2)

➕ According to the question,

$\implies$ x + (x + 1) + (x + 2) = 30

$\implies$ x + x + 1 + x + 2 = 30

$\implies$ x + x + x + 1 + 2 = 30

$\implies$ 3x + 3 = 30

$\implies$ 3x = 30 - 3

$\implies$ 3x = 27

$\implies$ x = $\sf\dfrac{\cancel{27}}{\cancel{3}}$

$\mapsto$ x = 9

$\therefore$ Least number will be 9.

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