The sum of three consecutive integers is −321. Find the three integers.
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Hey mate...
Here is your answer...
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Answered by
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HELLO DEAR FRIEND
Let 1st integer be x
so, 2nd integer will x + 1
3rd integer will x + 2
x + x + 1 + x + 2 = - 321
3x + 3 = 321
3x = 321 - 3
3x = 318
2nd integer = x + 1
= 108 + 1
= 109
.
3rd integer = x + 2
= 108 + 2
= 110
.
So, the required integers are
HOPE IT HELPS
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