Question

The sum of three consecutive integers is −321. Find the three integers.

Answer 1

Hey mate...

Here is your answer...

Hope this helps...!!!

Answer 2

HELLO DEAR FRIEND

Let 1st integer be x

so, 2nd integer will x + 1

3rd integer will x + 2

x + x + 1 + x + 2 = - 321

3x + 3 = 321

3x = 321 - 3

3x = 318

$\large{x = \frac{ \large{ 318}}{ \large{3 }} }$

$\large{ \boxed{ \bf{x = 108}}}$

2nd integer = x + 1

= 108 + 1

= 109

.

3rd integer = x + 2

= 108 + 2

= 110

.

So, the required integers are

$\huge \boxed{ \boxed{ \bf{108,109,110}} }$

HOPE IT HELPS