Question

the sum of three consecutive integers is 36

Answer 1

Hi !

Let the three consecutive integers be x , x +1 and x +2

given ,

x + (x + 1) + (x + 2) = 36

3x + 3 = 36

3(x + 1) = 36

x + 1 = 36/3

x + 1 = 12

x = 12 - 1

x = 11

x + 1 = 11 + 1 = 12

x + 2 = 11+ 2 = 13

Hence, the no:s are 11,12,13

Answer 2

HOPE THIS HELPS U. ....

x+x+1+x+2=36
3x+3=36
3x=36-3
3x=33
x=33/3
x=11
x+1 =12
x+2=13