the sum of three consecutive integers is 36. Find the integers
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(consecutive integers are numbers which are togther like 2,3,4)
let one be y
other be y+1
third be y+1+1
y+y+1+y+1+1 = 36
3y+3=36
3y = 36-3 = 33
y = 33/3
y = 11
one number is y = 11
second number is y+1 = 12
third number is y+1+1 = 13
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