Question

The sum of three consecutive integers is 36. what are the integers?

Answer 1

Let the first number integer be x, the second be x+1 and the third be x+2. A/Q x+(x+1)+(x+2)=36 x+x+1+x+2=36 3x+3=36 3x=36-3 3x=33 x=33/3 X=11 Therefore, the first integer is 11, the second is 12 and the third is 13

Answer 2

x, x+1, x+2 = 36

x+x+1+x+2 = 36

3x + 3 = 36

3x = 36-3

3x = 33

x = 33/3

x = 11

x = 11

x+1 = 12

x+2 = 13