the sum of three consecutive integers is 39. find all three integers.
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Answer:
one number =x
second number =x+1
Third number =x+2
x(x+1) (x+2) =39
x^2 + x(x+2) =39
x^2+ x^2+2x =39
x^4 + 2x =39
x^4 +2x -39 =0
x^4 +2-1 -39 =0
x^4(1-2) 39(1-2) =0
(x^4 +39) (1-2) = 0
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