The sum of three consecutive integers is 4 more than the smallest of the integers. Find the integers.
Answers
The sum of three consecutive integers is 4 more than the smallest of the integers. Find the integers.
refer to the attachment for your answer
THANKS
Step-by-step explanation:
Given :-
The sum of three consecutive integers is 4 more than the smallest of the integers.
To find :-
Find the integers?
Solution :-
Let the three consecutive integers be X, X+1 , X+2
The smallest integer = X
The sum of the three consecutive integers
=> X + X +1+ X+2
=> (X+X+X)+(1+2)
=> 3X+3
4 more than the smallest of the integers
=> X+4
According to the given problem
The sum of three consecutive integers is 4 more than the smallest of the integers.
=> 3X+3 = X+4
=> 3X-X = 4-3
=> 2X = 1
=> X = 1/2
1/2 is not an integer .
So it is not correct Question
Correction :-
The sum of three consecutive integers is 5 more than the smallest of the integers.
=> 3X+3 = X+5
=> 3X-X = 5-3
=> 2X = 2
=> X = 2/2
=> X = 1
and
X+1 = 1+1 = 2
X+2 = 1+2 = 3
Answer :-
The three consecutive integers are 1,2,3
Check:-
The three consecutive integers are 1,2,3
Their sum = 1+2+3 = 6
4more than the smallest integer = 5+1 = 6
The sum of three consecutive integers is 5 more than the smallest of the integers.
Verified the given relations in the given problem.