Question

the sum of three consecutive integers is 42 find the smallest integer in the list

Answer 1

let First Number = x -----------------------------------------------------> 12

 

then Second Number = x + 2 ------------------------------------------> 14

 

and Third Number = x + 4 ---------------------------------------------> 16

 

x + (x + 2) + (x + 4) = 42 ---> 3x + 6 = 42 ---> 3x = 36 ---> x = 12