The sum of three consecutive integers is 45. Find the integers.
Answers
Answer:
To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 45
3X + 3 = 45
3X + 3 - 3 = 45 - 3
3X = 42
3X/3 = 42/3
X = 14
Which means that the first number is 14, the second number is 14 + 1 and the third number is 14 + 2. Therefore, three consecutive integers that add up to 45 are 14, 15, and 16.
14 + 15 + 16 = 45
Step-by-step explanation:
plz follow
Answer:
FIRST NUMBER = 14
SECOND NUMBER = 15
THIRD NUMBER = 16
Step-by-step explanation:
LET THE FIRST CONSECUTIVE INTEGER BE X
; THE SECOND NUMBER BE X + 1
; THE THIRD NUMBER BE X + 2
GIVEN THAT SUM OF THESE NUMBERS IS 45
A/Q,
X + X + 1 + X + 2 = 45
=} 2X + X + 3 = 45
=} 3X + 3 = 45
=} 3X = 45 - 3
=} 3X = 42
=} X = 42 / 3
=} X = 14
HENCE , FIRST NUMBER = X = 14
SECOND NUMBER = X + 1
= 14 + 1
= 15
THIRD NUMBER = X + 2
= 14 + 2
= 16