Question

The sum of three consecutive integers is 45. Find the least of the three integers.
least integer = |​

Answer 1

✪ $\huge{\red{\underline{\overline{\mathbf{Question}}}}}$ ✪

→The sum of three consecutive integers is 45. Find the least of the three integers.

least integer = |

✪ $\huge{\green{\underline{\overline{\mathbf{Answer}}}}}$ ✪

⇒Given:

• Sum = 45
• Total consecutive number = 3

⇒To Find:

• All 3 Numbers

⇒Solution:

⇒Let First number be x

$\therefore$ Next two numbers will be x+1 & x+2

According to question:-

⇒$x+(x+1)+(x+2)=45$

⇒$3x+3=45$

⇒$3x=42$

⇒$x=\frac{42}{3}$

⇒$x=14$

All Numbers are:-

⇒$\huge{\pink{\overbrace{\underbrace{14 ,\:15,\:16}}}}$

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