Question

The sum of three consecutive integers is 45. Find the least of the three integers

Answer 1

Answer:

Step-by-step explanation: let these integers be x, 2 x and 3x

Answer 2

Answer:

14 , 15 and 16

Step-by-step explanation:

 Let the consecutive integers are a - 1 , a and a + 1.

Their sum = 45

     ⇒ ( a - 1 ) + a + ( a + 1 ) = 45

     ⇒ a - 1 + a + a + 1 = 45

     ⇒ a + a + a = 45

     ⇒ 3a = 45

     ⇒ a = 45/3 = 15

Hence, integers are a - 1 = 15 - 14

       a = 15

      a + 1 = 15 + 1 = 16