Question

The sum of three consecutive integers is 45. Find the least of the three integers.

Answer 1

Step-by-step explanation:

let integer are x, x+1,x+2

x+x+1+x+2=45

3x+3=45

3x=45-3

3x=42

x=42/3

x=14

second integer is 15,and third is 16

Answer 2

step by step:

1. integer= x
2. integer=x+1
3. integer=x+2  

x+x+1+x+2=45

3x+3=45

3x=45-3

3x=42

x=42/3

x=14    

1)integer=14

2)integer=15

3)integer=16

hope this helps you