The sum of three consecutive integers is 48. Find the numbers.
Answers
Answered by
7
Let the first no. be x
Then 2nd no. is x+1
And 3rd no. is x+2
A/q,
x+x+1+x+2 = 48
⇒ 3x = 48-3
⇒ x = 45/3
∴ x = 15
So, the 3 numbers are 15
15+1 = 16 and
15+2 = 17
Then 2nd no. is x+1
And 3rd no. is x+2
A/q,
x+x+1+x+2 = 48
⇒ 3x = 48-3
⇒ x = 45/3
∴ x = 15
So, the 3 numbers are 15
15+1 = 16 and
15+2 = 17
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Answered by
0
let three consecutive integers are x,( x+1) ,(x+2)
according to question
x+(x+1)+(x+2)= 48
3x+3=48
3x= 48-3
3x= 45
x=15
then, (x+1) = (15+1)=16
x+2 = 15+2 = 17
your three consecutive no. are 15, 16, 17
according to question
x+(x+1)+(x+2)= 48
3x+3=48
3x= 48-3
3x= 45
x=15
then, (x+1) = (15+1)=16
x+2 = 15+2 = 17
your three consecutive no. are 15, 16, 17
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