Question

The sum of three consecutive integers is 48. Find the numbers.

Answer 1

Let the first no. be x
Then 2nd no. is x+1
And 3rd no. is x+2

A/q,
        x+x+1+x+2 = 48
   ⇒ 3x = 48-3
   ⇒ x = 45/3
   ∴ x = 15

So, the 3 numbers are 15
                                     15+1 = 16 and
                                     15+2 = 17

Answer 2

let three consecutive integers are x,( x+1) ,(x+2)
according to question
x+(x+1)+(x+2)= 48
3x+3=48
3x= 48-3
3x= 45
x=15
then, (x+1) = (15+1)=16
x+2 = 15+2 = 17
your three consecutive no. are 15, 16, 17