Question

The sum of three consecutive integers is 48 . find the three integers

Answer 1

Step-by-step explanation:

let the three integers be,

x-1 , x , x+1

= -1 and 1 get cancelled so

3x=48

x=48÷3=16

x-1=16-1=15

x=16

x+1=16+1=17

so the three consecutive numbers are 15,16,17

hope it helps you

Answer 2

Answer:

Let the integers be:(x),(x-1),(x+1)

a/q:

x+x-1+x+1=48

3x=48

x=16

Hence,the integers will be :15,16 and 17

Hope this will help u...

Mark me brainliest ,if u really found it helpful.

THANKS

Step-by-step explanation: