Question

the sum of three consecutive integers is 48. find the three integers.

Answer 1

Answer:

By Given info, The numbers are consecutive.

Let the first number be x.

Thus, the numbers will be x, x+1, x+2.

By given info,

$x + (x + 1) + (x + 2) = 48 \\ \\ 3x + 3 = 48 \\ \\ x + 1 = 16 \\ \\ x = 15$

Thus, x = 15.

So, the numbers will be 15, 16, 17.

Answer 2

Answer:

-->Let the first number be x

-->The second and third consecutive numbers would be x + 1 and x + 2

Equation: x + (x + 1) + (x + 2) = 48

3x + 3 = 48

3x = 48 - 3

= 45

x = 45/3

= 15

• x = 15

• x + 1

ie, 15 + 1

= 16

• x + 2

ie, 15 + 2

= 17

Hence,

the three consecutive integers which add upto 48 are 15, 16 & 17.